You conduct a simple random sample of 12 of a particular species of monkey and measure their tails. The mean tail length of your sample is 15 cm. If we know that 1.2 cm is the standard deviation of the tail lengths of all monkeys in the population, then what is a 90% confidence interval for the mean tail length of all monkeys of this species?
Round ALL answers to 3 decimal places.
To compute this CI, I will need to use the distribution (z or t).
The critical value (from the table) that I need to compute the margin of error is: .
The margin of error for my interval is: .
The lower bound of my CI is: and the upper bound of my Ci is:
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