You are given n items sorted based on value ratio and the knapsack capacity is W. Now, what is the time complexity of fractional knapsack problem? weight O(n log n) O(n) O(n*n) O(nW) You are given 4...


You are given n items sorted based on value ratio and the knapsack capacity is W. Now, what<br>is the time complexity of fractional knapsack problem?<br>weight<br>O(n log n)<br>O(n)<br>O(n*n)<br>O(nW)<br>You are given 4 items as {value, weight} pairs in this format {{20, 5}, {60, 20}, {25, 10}, {X, 25}}. You can assume that the array is sorted<br>value<br>weight<br>ratio. The capacity of knapsack is 39. The item no. 4 (whose weight is 25 ) is taken fractionally to fill upto the knapsack<br>based on the<br>capacity. That fraction is represented in format. What is the lowest possible value of a?<br>For the question above, assume the total value stored in the knapsack is 132 after you have filled upto the knapsack capacity. What is the value<br>of X (in other words, the value of the item no. 4) ?<br>Give your answer to at least two decimal places.<br>

Extracted text: You are given n items sorted based on value ratio and the knapsack capacity is W. Now, what is the time complexity of fractional knapsack problem? weight O(n log n) O(n) O(n*n) O(nW) You are given 4 items as {value, weight} pairs in this format {{20, 5}, {60, 20}, {25, 10}, {X, 25}}. You can assume that the array is sorted value weight ratio. The capacity of knapsack is 39. The item no. 4 (whose weight is 25 ) is taken fractionally to fill upto the knapsack based on the capacity. That fraction is represented in format. What is the lowest possible value of a? For the question above, assume the total value stored in the knapsack is 132 after you have filled upto the knapsack capacity. What is the value of X (in other words, the value of the item no. 4) ? Give your answer to at least two decimal places.

Jun 04, 2022
SOLUTION.PDF

Get Answer To This Question

Related Questions & Answers

More Questions ยป

Submit New Assignment

Copy and Paste Your Assignment Here