X480: LinkedList - LinearNodes The LinearNode class is used to represent the individual nodes in a linear LinkedList. This particular LinkedList is doubly linked. Complete the LinearNode class. Your...


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X480: LinkedList - LinearNodes<br>The LinearNode class is used to represent the individual nodes in a linear LinkedList. This particular LinkedList is doubly linked. Complete the<br>LinearNode class.<br>Your Answer:<br>Feedback<br>Attempts remaining: 3<br>Your feedback will appear here when you check your answer.<br>1 private class LinearNode<E> {<br>3<br>public LinearNode (E element) {<br>4<br>5n<br>}<br>6.<br>public getPrev() {<br>8<br>public getNext() {<br>10<br>11<br>12<br>public getElem() {<br>13<br>14<br>}<br>15<br>public void setPrev( ){<br>16<br>17<br>}<br>18<br>public void setNext( ){<br>19<br>20<br>}<br>21<br>public void setElem(<br>24 }<br>License<br>Privacy<br>Contact<br>MacBook Pro<br>345<br>2222<br>

Extracted text: X480: LinkedList - LinearNodes The LinearNode class is used to represent the individual nodes in a linear LinkedList. This particular LinkedList is doubly linked. Complete the LinearNode class. Your Answer: Feedback Attempts remaining: 3 Your feedback will appear here when you check your answer. 1 private class LinearNode { 3 public LinearNode (E element) { 4 5n } 6. public getPrev() { 8 public getNext() { 10 11 12 public getElem() { 13 14 } 15 public void setPrev( ){ 16 17 } 18 public void setNext( ){ 19 20 } 21 public void setElem( 24 } License Privacy Contact MacBook Pro 345 2222
X806: Binary Search 1<br>Below is an implementation of binary search on a list of integers. Fill in the remaining lines to complete the method. You can always assume that int<br>ray [] will be an array sorted from smallest to largest<br>Your Answer:<br>Feedback<br>Attempts remaining: 3<br>Your feedback will appear here when you check your answer.<br>1 public int binarySearch1(int ray[], int target, int first, int last) {<br>if (first > last) {<br>return -1;<br>4<br>else {<br>(first + last) / 2;<br>if (ray[mid] == (target))<br>int mid<br>8<br>// Add return statement here!<br>if (ray[mid] < (target)) {<br>10<br>Add return statement here!<br>5.0<br>11<br>}<br>12<br>else {<br>13<br>// Add return statement here!<br>14<br>15<br>}7/ end else<br>16 }// end BSH1<br>17<br>Check my answer!<br>Reset<br>Next exercise<br>out<br>License<br>Privacy<br>Contact<br>МacBook Pro<br>20<br>000<br>000<br>II<br>2 3<br>

Extracted text: X806: Binary Search 1 Below is an implementation of binary search on a list of integers. Fill in the remaining lines to complete the method. You can always assume that int ray [] will be an array sorted from smallest to largest Your Answer: Feedback Attempts remaining: 3 Your feedback will appear here when you check your answer. 1 public int binarySearch1(int ray[], int target, int first, int last) { if (first > last) { return -1; 4 else { (first + last) / 2; if (ray[mid] == (target)) int mid 8 // Add return statement here! if (ray[mid] < (target)) { 10 add return statement here! 5.0 11 } 12 else { 13 // add return statement here! 14 15 }7/ end else 16 }// end bsh1 17 check my answer! reset next exercise out license privacy contact мacbook pro 20 000 000 ii 2 3 (target))="" {="" 10="" add="" return="" statement="" here!="" 5.0="" 11="" }="" 12="" else="" {="" 13="" add="" return="" statement="" here!="" 14="" 15="" }7/="" end="" else="" 16="" }//="" end="" bsh1="" 17="" check="" my="" answer!="" reset="" next="" exercise="" out="" license="" privacy="" contact="" мacbook="" pro="" 20="" 000="" 000="" ii="" 2="">
Jun 06, 2022
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