x+3 Let A = {; x

real analysisx+3<br>Let A = {; x < -5}. Then<br>1. 0 is a lower bound and<br>- is an upper bound of A.<br>is a lower bound and 1 is an upper bound of A.<br>is a lower bound and 2 is an upper bound of A.<br>3.<br>4. 1 is a lower bound and 2 is an upper bound of A.<br>e. None of these<br>O Option 1<br>O Option 2<br>O Option 3<br>Option 4<br>O Option 5<br>2.<br>

Extracted text: x+3 Let A = {; x < -5}.="" then="" 1.="" 0="" is="" a="" lower="" bound="" and="" -="" is="" an="" upper="" bound="" of="" a.="" is="" a="" lower="" bound="" and="" 1="" is="" an="" upper="" bound="" of="" a.="" is="" a="" lower="" bound="" and="" 2="" is="" an="" upper="" bound="" of="" a.="" 3.="" 4.="" 1="" is="" a="" lower="" bound="" and="" 2="" is="" an="" upper="" bound="" of="" a.="" e.="" none="" of="" these="" o="" option="" 1="" o="" option="" 2="" o="" option="" 3="" option="" 4="" o="" option="" 5="">

Jun 03, 2022
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