(x + 3)3 4(x – 1)2 12 16 Consider the function f(x) Note that 4 -1 (x – 1)2 (x – 9)(x + 3)² 4(x – 1)3 24(x + 3) f'(x) = and f"(x) = (r – 1)4 * - Use the Mean Value Theorem to show that the equation...

(x + 3)3<br>4(x – 1)2<br>12<br>16<br>Consider the function f(x)<br>Note that<br>4<br>-1<br>(x – 1)2<br>(x – 9)(x + 3)²<br>4(x – 1)3<br>24(x + 3)<br>f'(x) =<br>and f

Extracted text: (x + 3)3 4(x – 1)2 12 16 Consider the function f(x) Note that 4 -1 (x – 1)2 (x – 9)(x + 3)² 4(x – 1)3 24(x + 3) f'(x) = and f"(x) = (r – 1)4 * - Use the Mean Value Theorem to show that the equation f'(x) = 0.01 has a solution in the interval (-4,-3)

Jun 05, 2022

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(x + 3)3 4(x – 1)2 12 16 Consider the function f(x) Note that 4 -1 (x – 1)2 (x – 9)(x + 3)² 4(x – 1)3 24(x + 3) f'(x) = and f"(x) = (r – 1)4 * - Use the Mean Value Theorem to show that the equation...

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