work for similarity with previously published work and other student assignments. Details of its use in this unit will be placed on the vUWS site Report format (use these headings in your report)...

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work for similarity with previously published work and other student assignments. Details of its use in this unit will be placed on the vUWS site
Report format (use these headings in your report) Background _information: A brief justification of your experiment and how you decided upon the experimental design, Identify the dependent variable, independent variable and other variables that were controlled. (150 words maximum)
.e.e Your hypothesis: A statement of your null hypothesis (1 sentence) Methods: A flow diagram to explain your methodology. Details of both runs of the experiment must be included in the flow diagram. Remember that there should be enough detail for another person to repeat your experiment. (1 page maximum)
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Results: This section should include your results for both experiments in tables (and graphs if appropriate). Both raw data and appropriate calculations must be included and results should be expressed as cfu/ml or g or % reduction, In addition, the most significant results should be described in writing (max 100 words).
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Interpretation and conclusions: A concise analysis of what your results mean Asti and how they relate to relevant published information. State whether or not
you have disproved your hypothesis and justify your conclusion(s). (300 words maximum).
Critical evaluation of experimental design' Describe and explain any modifications that you made to your experimental design after the first experiment. Discuss how you could further improve your experimental design if you had more time and resources (300 words maximum).
References: Alphabetical list of references using the Harvard style. trscre 4
Marking Criteria The criteria and weightings that will be used to mark your report are provided In Appendix 10. Read through them carefully before completing your report.
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Answered Same DayDec 23, 2021

Answer To: work for similarity with previously published work and other student assignments. Details of its use...

David answered on Dec 23 2021
120 Votes
Background information:
The experiment was decided to find the effect of different media components on the growth of probiotic bacteria. Fat being a component was presumed not to affect the growth of bacteria . The dependent variables ,independent variables and different factors were al
so studied .
Dependent Variable:
· The number viable lactobacillus in solution after it is exposed to the treatment.
Independent Variable:
· The additional of fat (cream) to the diluted culture of lactobacillus .
Controlled Variable:
· Type of bacterial (lactobacillus)
· Type of broth used to culture
· The experiment is preformed under controlled laboratory conditions
· Contamination of equipment is prevented by aseptic techniques
· Method of counting the bacteria (lactobacillus)
· Amount of HCl added to the bacteria (lactobacillus).
Control:
· Total number of bacteria (lactobacillus) in the initial broth (109 cfu/ml).
Your hypothesis: Fat does not affect the survival of probiotic bacteria (lactobacillus).
Methods:
The expts were carried out in 2 different ways and results were also analysed in that way also .
EXPT 1 :-
Control Treatment
EXPT 2 :-

RESULTS :-
Experiment 1:
    Dilution factor
    Control
    1:4
    1:1
    
    Plate 1
    Plate 2
    
    Plate 1
    Plate 2
    average
    Plate 1
    Plate 2
    average
    10⁻6
    TNTC
    TNTC
    
    TNTC
    TNTC
    
    TNTC
    TNTC
    
    10⁻7
    75
    107
    
    TNTC
    TNTC
    
    TNTC
    TNTC
    
    10⁻8
    12
    10
    
    50
    6
    
    TNTC
    TNTC
    
Experiment 2:
    Dilution
factor
    control
    Treatment
    
    
    Incubated lacto acid
    Lacto acid cream
    Lacto + acid
    
    Plate 1
    Plate 2
    Average
    Plate 1
    Plate 2
    Average
    Plate 1
    Plate 2
    Average
    Plate 1
    Plate 2
    Average
    10⁻6
    
    78
    119
    
    60
    60
    
    TNTC
    -----
    
    10⁻7
    68
    62
    
    6
    3
    
    6
    4
    
    17
    25
    
    10⁻8
    
    1
    0
    
    0
    0
    
    2
    -----
    
EXPERIMENT 1 RESULTS ANDINTERPRETATION :-
From expt 1 so conducted individually for each dilutions the CFU count should be calculated .
For 10-6dilution :-
For control and the two test samples no result was obtained because the plate exceeded the thumb rule of plate count (25-250 colonies).
For 10-7dilution :-
For control ,the no. of colonies found is 91(by considering average of the two plates) and hence by the formula for CFU counting we found that 9.1 x 108cfu /ml is present . however the scenario for the test samples was distinct from the control one because the plates had colonies which were too numerous to count .
For 10-8dilution :-
For control, the no of colonies is 11 (by average consideration of the two plates) which is low to be considered for counting colonies and CFU also ,where as the for the test samples in case of 1:4 mixture the average so obtained was 28 colonies and hence the CFU count is 9.33 x 108cfu/ml and the last test case of 1:1 has no...
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