words_for_homework (1).txt aalii aardvark aardvarks aardwolf aba abaca abaci abacist aback abacus abacuses abaft abalone abalones abamp abampere abandon abandoned abandonee abandoner abandoners...


I need help with my Java programming project. The project will be completed in Eclipse so if you could also help guide me through by labeling what section is what so I'm not trying to guess that would be great. Thanks



words_for_homework (1).txt<br>aalii<br>aardvark<br>aardvarks<br>aardwolf<br>aba<br>abaca<br>abaci<br>abacist<br>aback<br>abacus<br>abacuses<br>abaft<br>abalone<br>abalones<br>abamp<br>abampere<br>abandon<br>abandoned<br>abandonee<br>abandoner<br>abandoners<br>abandoning<br>abandonment<br>abandons<br>abase<br>abased<br>abasement<br>abaser<br>abasers<br>abases<br>

Extracted text: words_for_homework (1).txt aalii aardvark aardvarks aardwolf aba abaca abaci abacist aback abacus abacuses abaft abalone abalones abamp abampere abandon abandoned abandonee abandoner abandoners abandoning abandonment abandons abase abased abasement abaser abasers abases
The following is an old word puzzle:
4) { if (line.substring(line.length() - 4, line.length()).equalsIgnoreCase("dous")) { fw.write(line + "\n"); } } line = br.readLine(); } "/>
Extracted text: The following is an old word puzzle: "Name a common word, besides tremendous, stupendous and horrendous, that ends in dous." We can also solve this puzzle by reading a text file of English words and outputting the word if it contains "dous" at the end. The text file "words_for_homework.txt" contains 87314 English words, including the word that completes the puzzle. Write a program that reads each word from the attached text file (words_for_homework.txt) and writes only those containing "dous" at the end to another file. Below is a hint at the code to get at the dous. Include exception handling to catch any errors with the files. Use the finally block to close the files. Zip the project folder and upload here. Code Hint for -dous: String line br.readLine(); %3D while (line != null) { if (line.length() > 4) { if (line.substring(line.length() - 4, line.length()).equalsIgnoreCase("dous")) { fw.write(line + "\n"); } } line = br.readLine(); }

Jun 11, 2022
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