When calling a swap function to swap the value of the two arrays, how do I add the reference to the calling statement without giving me an error? Also, I have to use pointers for this assignment. Here...

When calling a swap function to swap the value of the two arrays, how do I add the reference to the calling statement without giving me an error? Also, I have to use pointers for this assignment.

Here is the code:

const int S = 10;

//Pre-condition: two c strings of the same size

//Post-condition: swap the values of the c strings

void swapArr(char array1[ S], char array2[ S]) {

int size = 0;
for (int i = 0; array1[1] != '\0'; i++) {
size++;
}

char* value = new char;
value = new char [size];
//Loop fusion
for (int i = 0; i < size;="" i++)="">
  //Swap the values
  value[i] = array1[i];
  array1[i] = array2[i];
  array2[i] = value[i];
}

}

int main(){

char array1[S]= { "Hello" };
char array2[S] = { "World"};

//For some reason the swap function is not working

swapArr(& array1[S], & array2[S]);

for (int i = 0; array1[i] != '\0'; i++) {
std::cout <>
}

}

Jun 05, 2022

SOLUTION.PDF

When calling a swap function to swap the value of the two arrays, how do I add the reference to the calling statement without giving me an error? Also, I have to use pointers for this assignment. Here...

Get Answer To This Question

Related Questions & Answers

Submit New Assignment