We have k = 0.55 · 12 = 6.6= 6, so that α = 0.6. This gives qn(0.55) = x XXXXXXXXXX · (x(7) − x(6)) = XXXXXXXXXX · (43 − 42) = 42.6. 2. From the order statistics of the Wick temperature data it can be...

We have k = 0.55 · 12 = 6.6= 6, so that α = 0.6. This gives

qn(0.55) = x(6) + 0.6 · (x(7) − x(6)) = 42 + 0.6 · (43 − 42) = 42.6.

2. From the order statistics of the Wick temperature data

it can be seen immediately that minimum, maximum, and median are given by 41, 58, and 42. For the lower quartile we have k = 0.25·12 = 3, so that α = 0 and qn(0.25) = x(3) = 41. For the upper quartile we have k = 0.75 · 12 = 9, so that again α = 0 and qn(0.75) = x(9) = 43. Hence for the Wick temperature data the five-number summary is