= vr2 – x2, whose graph is the upper 6. Let r > 0 be a real number. Suppose y = semi-circle of radius r about the origin. f (x) (a) Calculate and simplify the expressions V1+ f'(x)² and f(x)/1+...


= vr2 – x2, whose graph is the upper<br>6. Let r > 0 be a real number. Suppose y =<br>semi-circle of radius r about the origin.<br>f (x)<br>(a) Calculate and simplify the expressions V1+ f'(x)² and f(x)/1+ f'(x)².<br>(b) Suppose -r < a < b < r. Calculate the surface area of the portion of the sphere of<br>radius r between x = a and x =<br>= b.<br>(c) Imagine cutting a spherical orange by equidistant parallel planes. (An orange cut into<br>nine equal-width pieces is shown.) Which pieces do you expect to have the most rind:<br>Those near

Extracted text: = vr2 – x2, whose graph is the upper 6. Let r > 0 be a real number. Suppose y = semi-circle of radius r about the origin. f (x) (a) Calculate and simplify the expressions V1+ f'(x)² and f(x)/1+ f'(x)². (b) Suppose -r < a="">< b="">< r.="" calculate="" the="" surface="" area="" of="" the="" portion="" of="" the="" sphere="" of="" radius="" r="" between="" x="a" and="" x="=" b.="" (c)="" imagine="" cutting="" a="" spherical="" orange="" by="" equidistant="" parallel="" planes.="" (an="" orange="" cut="" into="" nine="" equal-width="" pieces="" is="" shown.)="" which="" pieces="" do="" you="" expect="" to="" have="" the="" most="" rind:="" those="" near="" "the="" poles",="" or="" those="" near="" "the="" equator"?="" how="" does="" your="" intuition="" compare="" with="" the="" result="" of="">

Jun 04, 2022
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