Video Example ) 2xy2 3x2 + yA EXAMPLE 3 If f(x, y) = does lim (x, y)- (0, 0) f(x, y) exist? SOLUTION Let's try to save some time by letting (x, y) → (0, 0) along any nonvertical line through the...

Please solve correctly in 20 minutes fill Al the boxes and get the thumbs upVideo Example )<br>2xy2<br>3x2 + yA<br>EXAMPLE 3<br>If f(x, y) =<br>does<br>lim<br>(x, y)- (0, 0)<br>f(x, y) exist?<br>SOLUTION Let's try to save some time by letting (x, y) → (0, 0) along any<br>nonvertical line through the origin. Then y = mx, where m is the slope, and<br>f(x, у) %3D f(x, тх) %3<br>3x² + (mx)ª<br>3x2 + mªx4<br>3 + m*x<br>So f(x, y) →<br>as (x, y) → (0, 0) along y = mx.<br>Thus f has the same limiting value along every nonvertical line through the origin.<br>But that does not show that the given limit is 0, for if we now let (x, y) → (0, 0)<br>along the parabola x = y?, we have<br>f(x, y) = f(y², y) =<br>3(y²)² + yA<br>4y4<br>So f(x, y) →<br>as (x, y) → (0, 0) along x = y².<br>Since different paths lead to different limiting values, the given limit does not<br>exist.<br>

Extracted text: Video Example ) 2xy2 3x2 + yA EXAMPLE 3 If f(x, y) = does lim (x, y)- (0, 0) f(x, y) exist? SOLUTION Let's try to save some time by letting (x, y) → (0, 0) along any nonvertical line through the origin. Then y = mx, where m is the slope, and f(x, у) %3D f(x, тх) %3 3x² + (mx)ª 3x2 + mªx4 3 + m*x So f(x, y) → as (x, y) → (0, 0) along y = mx. Thus f has the same limiting value along every nonvertical line through the origin. But that does not show that the given limit is 0, for if we now let (x, y) → (0, 0) along the parabola x = y?, we have f(x, y) = f(y², y) = 3(y²)² + yA 4y4 So f(x, y) → as (x, y) → (0, 0) along x = y². Since different paths lead to different limiting values, the given limit does not exist.

Jun 04, 2022
SOLUTION.PDF

Get Answer To This Question

Related Questions & Answers

More Questions »

Submit New Assignment

Copy and Paste Your Assignment Here