V2 (j) + Vs (z) = 120 L-60° a). V2 + 2 V3 12o (-15O (1). Step-2:- By applsing Analy sis at Nodal V3: V3- Vz V3 V3- 60C30" -4 jio - ju J. jio -4 - 60C30° jio 8 32+ 60C30" 10 V3 (-4j+ 10j + 5) + Ve (ui)...

Write a routine in Python to solve the circuits of the images, of up to 5 nodes. (The exercise is already solved)V2 (j) + Vs (z) =<br>120 L-60° a).<br>V2 +<br>2 V3<br>12o (-15O<br>(1).<br>Step-2:-<br>By applsing<br>Analy sis at<br>Nodal<br>V3:<br>V3- Vz<br>V3<br>V3- 60C30

Extracted text: V2 (j) + Vs (z) = 120 L-60° a). V2 + 2 V3 12o (-15O (1). Step-2:- By applsing Analy sis at Nodal V3: V3- Vz V3 V3- 60C30" -4 jio - ju J. jio -4 - 60C30° jio 8 32+ 60C30" 10 V3 (-4j+ 10j + 5) + Ve (ui) 32+ 51.96+ j30 V3 ( 5+63) + Vz (uj) = s[ 83.96+ j30). V3 (s+6] + Uz (uj) = 419.8 + ji5o Vs | 7.81 (50-196) + v2 (4L90")= 4u5.79 (19.66° -(2) · By solviug e9.. (2) 4 (3); get -87.895- j 279.862 293· 34 L 252.56°V - 8.01 + ji09.931 V3 : 110. 22 94•167° v voltage values are v, = 60L30° u; V2 = 293. 34 (252.56°v Vg = 110.22/94167°v Hence solved
step-1:<br>Given<br>Ne kwork-<br>jior<br>jion.<br>60 (30°J<br>- ju r<br>-jue<br>(T) UL0°A<br>fsom khe<br>circuit,<br>60 (30°<br>By applying<br>Analysis<br>Node-ve<br>-><br>Nodal<br>at<br>V2 - 60 (30°<br>V2 - V3<br>Jio<br>- ju<br>jio<br>V2<br>60 L30°<br>+<br>jio<br>10<br>jV3<br>2<br>- j6 L30°<br>%3D<br>jio<br>10<br>Vz<br>jv3<br>十<br>6[30-90°.<br>10<br>4<br>Vz (-4j + 5i)<br>+ 2j v3<br>6 60°<br>%3D<br>20<br>

Extracted text: step-1: Given Ne kwork- jior jion. 60 (30°J - ju r -jue (T) UL0°A fsom khe circuit, 60 (30° By applying Analysis Node-ve -> Nodal at V2 - 60 (30° V2 - V3 Jio - ju jio V2 60 L30° + jio 10 jV3 2 - j6 L30° %3D jio 10 Vz jv3 十 6[30-90°. 10 4 Vz (-4j + 5i) + 2j v3 6 60° %3D 20

Jun 11, 2022
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