V2 (72 + j104) V V3 = (150 - j130) V 1 =(-26- j52) A 1, = (-2+ j6) A L = (-24 – j58) A Copyright 0 2011 Pearson Educatlion, Inc. publishing as Prenice Hall Note: The given values are not RMS values...

V2 (72 + j104) V<br>V3 = (150 - j130) V<br>1 =(-26- j52) A<br>1, = (-2+ j6) A<br>L = (-24 – j58) A<br>Copyright 0 2011 Pearson Educatlion, Inc. publishing as Prenice Hall<br>Note: The given values are not RMS values<br>Select one:<br>O a.<br>3880 VAR<br>O b. 2500 VAR<br>O c.<br>6760 VAR<br>O d. 3380 VAR<br>

Extracted text: V2 (72 + j104) V V3 = (150 - j130) V 1 =(-26- j52) A 1, = (-2+ j6) A L = (-24 – j58) A Copyright 0 2011 Pearson Educatlion, Inc. publishing as Prenice Hall Note: The given values are not RMS values Select one: O a. 3880 VAR O b. 2500 VAR O c. 6760 VAR O d. 3380 VAR

.Given the circuit below and the associated set of voltages and currents, the reactive Power developed by j20<br>inductor is<br>V1<br>V3<br>j2 N +<br>j3 N<br>12Ωξ<br>39 I,<br>-j16 N<br>V, = 150 /0° V<br>V (78- j104) V<br>V2 = (72 +j104) V<br>V = (150- j130) V<br>I, = (-26 - 52) A<br>1, = (-2 + j6) A<br>I = (-24 - j58) A<br>!!<br>Copyrighto 2011 Pearsoe Edcation, inc putisheng as Prensce Hal<br>Note: The given values are not RMS values<br>

Extracted text: .Given the circuit below and the associated set of voltages and currents, the reactive Power developed by j20 inductor is V1 V3 j2 N + j3 N 12Ωξ 39 I, -j16 N V, = 150 /0° V V (78- j104) V V2 = (72 +j104) V V = (150- j130) V I, = (-26 - 52) A 1, = (-2 + j6) A I = (-24 - j58) A !! Copyrighto 2011 Pearsoe Edcation, inc putisheng as Prensce Hal Note: The given values are not RMS values

Jun 11, 2022

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V2 (72 + j104) V V3 = (150 - j130) V 1 =(-26- j52) A 1, = (-2+ j6) A L = (-24 – j58) A Copyright 0 2011 Pearson Educatlion, Inc. publishing as Prenice Hall Note: The given values are not RMS values...

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