с. v = 3 d. v = 4 What is your conclusion? a. Reject H0 b. Do Not Reject H0 c. This test has no conclusion


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с.<br>v = 3<br>d. v = 4<br>What is your conclusion?<br>a. Reject H0<br>b. Do Not Reject H0<br>c. This test has no conclusion<br>

Extracted text: с. v = 3 d. v = 4 What is your conclusion? a. Reject H0 b. Do Not Reject H0 c. This test has no conclusion
Problem l) A survey of 30-year-old males provided data on the number of auto accidents in the<br>previous 5 years. The sample mean is 1.3 accidents per male. Test the hypothesis that the<br>number of accidents follows a Poisson distribution at the 5% level of significance.<br>No. of accidents<br>No. of males<br>33<br>1<br>36<br>2<br>25<br>3<br>11<br>> 4<br>4<br>What's the Expected probability of finding males with 0 accidents?<br>a. 0.0202<br>b. 0.3332<br>c. 0.0256<br>d. 0.2725<br>What's the Expected probability of finding males with 4 or more accidents?<br>a. 0.0431<br>b. 0.3332<br>c. 0.0256<br>d. 0.1280<br>What is the total Chi-value?<br>а.<br>1.870<br>b. 6.373<br>c. 4.543<br>d. 0.564<br>What is the Chi-square critical value?<br>a. 7.815<br>b. 6.635<br>c. 5.991<br>d. 3.841<br>What is the degrees of freedom associated with this test?<br>a. v= 1<br>b. v=2<br>

Extracted text: Problem l) A survey of 30-year-old males provided data on the number of auto accidents in the previous 5 years. The sample mean is 1.3 accidents per male. Test the hypothesis that the number of accidents follows a Poisson distribution at the 5% level of significance. No. of accidents No. of males 33 1 36 2 25 3 11 > 4 4 What's the Expected probability of finding males with 0 accidents? a. 0.0202 b. 0.3332 c. 0.0256 d. 0.2725 What's the Expected probability of finding males with 4 or more accidents? a. 0.0431 b. 0.3332 c. 0.0256 d. 0.1280 What is the total Chi-value? а. 1.870 b. 6.373 c. 4.543 d. 0.564 What is the Chi-square critical value? a. 7.815 b. 6.635 c. 5.991 d. 3.841 What is the degrees of freedom associated with this test? a. v= 1 b. v=2

Jun 09, 2022
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