Using your solution to Exercise 5.5 (or Exercise 5.14, for that matter), test the hypothesis H : b2 = 2b3; follow both routes considered in Section 5.10 as well as the straightforward expression...

Using your solution to Exercise 5.5 (or Exercise 5.14, for that matter), test the hypothesis H : b2 = 2b3; follow both routes considered in Section 5.10 as well as the straightforward expression

                     (KTbˆ − m) T[KT (XTX) −1 K] −1 (KTbˆ − m).

Discuss how a comparison could be made among the methods.