Using the substitution y = vx and dy = v dx+ x dv, the differential equation with homogeneous coefficients (x2 + y?)dx + xy dy = 0 reduces to %3| None of the given choices В (1+2v)dx + x dv = 0 (2v2 -...

Using the substitution y = vx and dy = v dx+ x dv, the<br>differential equation with homogeneous coefficients<br>(x2 + y?)dx + xy dy = 0 reduces to<br>%3|<br>None of the given choices<br>В<br>(1+2v)dx + x dv = 0<br>(2v2 - 1)dx + vx dv = 0<br>D<br>(1+2v)dx + vx dv = 0<br>E<br>(2v2 – 1)dx – vx dv = 0<br>%3D<br>

Extracted text: Using the substitution y = vx and dy = v dx+ x dv, the differential equation with homogeneous coefficients (x2 + y?)dx + xy dy = 0 reduces to %3| None of the given choices В (1+2v)dx + x dv = 0 (2v2 - 1)dx + vx dv = 0 D (1+2v)dx + vx dv = 0 E (2v2 – 1)dx – vx dv = 0 %3D

Jun 05, 2022

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Using the substitution y = vx and dy = v dx+ x dv, the differential equation with homogeneous coefficients (x2 + y?)dx + xy dy = 0 reduces to %3| None of the given choices В (1+2v)dx + x dv = 0 (2v2 -...

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