Using the substitution y = vx and dy = v dx+ x dv, the differential equation with homogeneous coefficients (x2 + y?)dx + xy dy = 0 reduces to A (2v2 – 1)dx – vx dv = 0 В None of the given Choices...

Using the substitution y = vx and dy = v dx+ x dv, the<br>differential equation with homogeneous coefficients<br>(x2 + y?)dx + xy dy = 0 reduces to<br>A<br>(2v2 – 1)dx – vx dv = 0<br>В<br>None of the given Choices<br>(1+2v)dx + vx dv = 0<br>%3D<br>D<br>(1+2v2)dx + x dv = 0<br>E<br>(2v2 - 1)dx + Vx dv = 0<br>

Extracted text: Using the substitution y = vx and dy = v dx+ x dv, the differential equation with homogeneous coefficients (x2 + y?)dx + xy dy = 0 reduces to A (2v2 – 1)dx – vx dv = 0 В None of the given Choices (1+2v)dx + vx dv = 0 %3D D (1+2v2)dx + x dv = 0 E (2v2 - 1)dx + Vx dv = 0

Jun 05, 2022

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Using the substitution y = vx and dy = v dx+ x dv, the differential equation with homogeneous coefficients (x2 + y?)dx + xy dy = 0 reduces to A (2v2 – 1)dx – vx dv = 0 В None of the given Choices...

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