Use the probability distribution to complete parts (a) and (b) below. The number of defects per 1000 machine parts inspected Defects 1 2 3 4 Probability 0.264 0.289 0.238 0.156 0.037 0.016 The...


Question B., I'm to see which answers are correct for


b.2 : the average batch of 1000 machines parts has _________


b.4: The standard deviation is 1.2, so the typical number of defects in a batch of 1000 _________


Use the probability distribution to complete parts (a) and (b) below.<br>The number of defects per 1000 machine parts inspected<br>Defects<br>1<br>2<br>3<br>4<br>Probability 0.264<br>0.289<br>0.238<br>0.156<br>0.037<br>0.016<br>The variance is 1.5.<br>deviates from the mean by more than 2 defects.<br>(Round to one decimal place as need<br>does not deviate from the mean.<br>The standard deviation is 1.2.<br>(Round to one decimal place as need<br>deviates from the mean by about 1 defect.<br>(b) Interpret the results.<br>deviates from the mean by about 2 defects.<br>The mean is 1.5. so the average bat<br>number of defects in a batch of 1000 does not deviate from the mean.<br>(Round to one decimal place as needed.)<br>dard deviation is 1.2, so the typical<br>

Extracted text: Use the probability distribution to complete parts (a) and (b) below. The number of defects per 1000 machine parts inspected Defects 1 2 3 4 Probability 0.264 0.289 0.238 0.156 0.037 0.016 The variance is 1.5. deviates from the mean by more than 2 defects. (Round to one decimal place as need does not deviate from the mean. The standard deviation is 1.2. (Round to one decimal place as need deviates from the mean by about 1 defect. (b) Interpret the results. deviates from the mean by about 2 defects. The mean is 1.5. so the average bat number of defects in a batch of 1000 does not deviate from the mean. (Round to one decimal place as needed.) dard deviation is 1.2, so the typical
Use the probability distribution to complete parts (a) and (b) below.<br>The number of defects per 1000 machine parts inspected<br>Defects<br>1<br>2<br>4<br>5<br>Probability 0.264<br>0.289<br>0.238<br>0.156<br>0.037<br>0.016<br>The variance is 1.5.<br>at least 2 defects.<br>(Round to one decimal place as needed.)<br>The standard deviation is 1.2.<br>1 or 2 defects.<br>(Round to one decimal place as needed.)<br>no defects.<br>(b) Interpret the results.<br>The mean is 1.5, so the average batch of 1000 machine parts has at least 2 defects. The standard deviation is 1.2, so the typical<br>number of defects in a batch of 1000 does not deviate from the mean.<br>(Round to one decimal place as needed.)<br>

Extracted text: Use the probability distribution to complete parts (a) and (b) below. The number of defects per 1000 machine parts inspected Defects 1 2 4 5 Probability 0.264 0.289 0.238 0.156 0.037 0.016 The variance is 1.5. at least 2 defects. (Round to one decimal place as needed.) The standard deviation is 1.2. 1 or 2 defects. (Round to one decimal place as needed.) no defects. (b) Interpret the results. The mean is 1.5, so the average batch of 1000 machine parts has at least 2 defects. The standard deviation is 1.2, so the typical number of defects in a batch of 1000 does not deviate from the mean. (Round to one decimal place as needed.)
Jun 09, 2022
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