Use the probability distribution to complete parts (a) and (b) below. The number of defects per 1000 machine parts inspected Defects 0 1 2 3 4 5 Probability 0.258 0.297 0.231 0.152 0.043 0.19 a)...

Use the probability distribution to complete parts (a) and (b) below.

The number of defects per 1000 machine parts inspected

Defects	0	1	2	3	4	5
Probability	0.258	0.297	0.231	0.152	0.043	0.19

a) Find the mean, variance, and standard deviation of the probability distribution.

The mean is

nothing.

(Round to one decimal place as needed.)

The variance is

nothing.

(Round to one decimal place as needed.)

The standard deviation is

nothing.

(Round to one decimal place as needed.)

(b) Interpret the results.

The mean is

nothing,

so the average batch of 1000 machine parts has

▼

at least 2 defects.

no defects.

1 or 2 defects.

The standard deviation is

nothing,

so the typical number of defects in a batch of 1000

▼

does not deviate from the mean.

deviates from the mean by more than 2 defects.

deviates from the mean by about 1 defect.

deviates from the mean by about 2 defects.

(Round to one decimal place as needed.)

Jun 09, 2022

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