Use the following table to answer the questions below: Table name: Customers Column Name Role Data Type Length Constraint customerID stores the ID of a customer Char 5 Primary key custFName stores the...


Use the following table to answer the questions below:



























































Table name: Customers




Column Name




Role




Data Type




Length




Constraint



customerID



stores the ID of a customer



Char



5



Primary key



custFName



stores the first name of a customer



Varchar2



35



Cannot be null



custLName



Stores the last name of a customer



Varchar2



35



Cannot be null



custGender



Store the gender of a customer



Char



1



It should be ‘M’ or ‘F’



custDOB



Stores the date of birth of a customer



Date



custIncome



Store the income of a customer



Number



4







  1. Write in SQL a command that creates the table Customers according to the above description (2 marks).

  2. Write in SQL a statement that adds a new column named accountID of type Char(8). This column should be defined as a foreign key that relates the table Customers to the table Account (1.5 marks).

  3. Write in SQL a command that deletes the customers whose date of birth is after 22-Dec-1990 (1.5 Marks).

  4. Write a SQL query that displays the number of customers who born on the 16th day of a month (1.5 marks).

  5. Write in SQL a query that displays the ids of the customers who have the highest income (1.5 marks).

  6. Create a view named ‘customerDetails’ to hold all the details of customers whose first names start with ‘S’ and their incomes are between 500 and 1000 Omani Rials (2 marks).



Jun 07, 2022
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