Use Fisher's LSD procedure to test whether there is a significant difference between the means for treatments A and B, treatments A and C, and treatments B and C. Use a = 0.05. Difference Absolute...


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Use Fisher's LSD procedure to test whether there is a significant difference between the means for treatments A and B, treatments A and C, and treatments B and C. Use a = 0.05.<br>Difference Absolute Value<br>Conclusion<br>TA - TB<br>Significant difference<br>TA - EG<br>Significant difference<br>Significant difference<br>c. Use Fisher's LSD procedure to develop a 95% confidence interval estimate of the difference between the means of treatments A and B (to 2 decimals). Enter negative values as negative numbers.<br>

Extracted text: Use Fisher's LSD procedure to test whether there is a significant difference between the means for treatments A and B, treatments A and C, and treatments B and C. Use a = 0.05. Difference Absolute Value Conclusion TA - TB Significant difference TA - EG Significant difference Significant difference c. Use Fisher's LSD procedure to develop a 95% confidence interval estimate of the difference between the means of treatments A and B (to 2 decimals). Enter negative values as negative numbers.
The following data are from a completely randomized design.<br>Treatment Treatment Treatment<br>A<br>B<br>32<br>46<br>35<br>30<br>45<br>38<br>30<br>46<br>37<br>26<br>48<br>38<br>32<br>50<br>42<br>Sample mean<br>30<br>47<br>38<br>Sample variance<br>6.00<br>4.00<br>6.50<br>a. At the a = 0.05 level of significance, can we reject the null hypothesis that the means of the three treatments are equal?<br>Compute the values below (to 1 decimal, if necessary).<br>Sum of Squares, Treatment<br>Sum of Squares, Error<br>Mean Squares, Treatment<br>Mean Squares, Error<br>Calculate the value of the test statistic (to 2 decimals).<br>The p-value is less than 0.01<br>What is your conclusion?<br>Conclude that not all treatment means are equal<br>b. Calculate the value of Fisher's LSD (to 2 decimals).<br>

Extracted text: The following data are from a completely randomized design. Treatment Treatment Treatment A B 32 46 35 30 45 38 30 46 37 26 48 38 32 50 42 Sample mean 30 47 38 Sample variance 6.00 4.00 6.50 a. At the a = 0.05 level of significance, can we reject the null hypothesis that the means of the three treatments are equal? Compute the values below (to 1 decimal, if necessary). Sum of Squares, Treatment Sum of Squares, Error Mean Squares, Treatment Mean Squares, Error Calculate the value of the test statistic (to 2 decimals). The p-value is less than 0.01 What is your conclusion? Conclude that not all treatment means are equal b. Calculate the value of Fisher's LSD (to 2 decimals).

Jun 09, 2022
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