Untitled College PhysicsCoulomb’s Law-Part 2EPCC Show your work on a separate document. Block or highlight your answers. Limit your responses to within 3 sentences. Use your own sketches to help...

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Answered 6 days AfterJul 20, 2021

Answer To: Untitled College PhysicsCoulomb’s Law-Part 2EPCC Show your work on a separate document. Block or...

Rahul answered on Jul 27 2021
150 Votes
Solution-1. To counter balance mgsinѲ component, electrostatic force between q1 and q2 should be opposite to mgsinѲ. This is possible if q1 and q2 repel each other.
Since q1 is positive q2 should also be positive.
To calculate distance between two objects,
felectrostatic= mgsinѲ
r2=
9×109×3×10-3×3×10-3
10×10×1/2
r=40.24 m
Solution-2.
q1 F32Sin60 F32 (force on 3 due to 2)
(
F
32
Cos60 + F
31
Cos60
)
(
q
2
) F31 Sin 60 F31 (force on 3 due to 1)

F = F31 = F32 = 9 x 10 9 x 2 x 10 -4 x 1 x 10-3/ 12
F31 Sin 60 and F32Sin60 cancelled out due to equal magnitude and opposite...
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