R= R'(1+ R'/Ry)
WhereR’ =V/I is the measured resistance as given by the voltmeter and current readings andRV is the actual resistance of the voltmeter. (Note thatR’/RV is essentially the error of your measurements) Is the true resistance larger or smaller than the apparent resistance?
Hint: use the binomial theorem:
___1_______ = 1 + __R'___
1 -(R'/ Ry) Ry
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