uniform and normal distribution

Answered Same DayDec 21, 2021

Answer To: uniform and normal distribution

David answered on Dec 21 2021

129 Votes

Solution 1
Part (a)
We need to find
P(X5 – P(0So the probability that Bombardiers service share will be lower in 2014 as compare to 2010 is 0.15866.
Part (b)
We need to find
P(X>x) = P((X-mean)/sd>54-51/2) = P(Z<3/2) = P(Z>1.5) = 0.5 – P(0=0.06681
So the probability that Rolls-Royce service share will be higher in 2014 as compare to 2010 is 0.06681.
Part (c)
The assumptions are:
The central limit theorem basically states that as the sample size (N) becomes large, the following occur:
1. The sampling distribution of the mean becomes approximately normal regardless of the
distribution of the original variable.
2. The sampling distribution of the mean...

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uniform and normal distribution

Answer To: uniform and normal distribution

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