To I2 1.2kW 0-8KVA 100290° V 2KVA 0.707led |4kW, 0.9 lag S3 Solution: here S2= 12-jo·8 kVA S3= 4 +i 4. Sinto-g) = 4+jl.937 kA 0.9 here S4 5:2+jl·137 KVA 米 %3D 254 2152 +jl·137)x103 22-74- 104 now I Vo...

how does the equation for s_3 make sense? i think here might be a calculation error

To<br>I2<br>1.2kW<br>0-8KVA<br>100290° V<br>2KVA 0.707led<br>|4kW, 0.9 lag<br>S3<br>Solution: here S2= 12-jo·8 kVA<br>S3= 4 +i 4. Sinto-g) =<br>4+jl.937 kA<br>0.9<br>here S4<br>5:2+jl·137 KVA<br>米<br>%3D<br>254<br>2152 +jl·137)x103<br>22-74- 104<br>now I<br>Vo<br>100 296<br>hence Iz<br>22.74 +j104 A<br>Similarly, si = 5- 2 sin Can-l(o-707)) = (1-;)kVA<br>O.707<br>T,* = 251<br>(2-824 -i2-3234)XLO3<br>= - 28.234-j 28.284 A<br>%3D<br>1 100<br>- 23.284+i 28. 284 A<br>how Io = I, +I2=<br>(22-74 +j lo 4)+(-23.284 -j 23-284 ) A<br>- 5544 +j 132.23 =1 32:44 92-4° A<br>%3D<br>

Extracted text: To I2 1.2kW 0-8KVA 100290° V 2KVA 0.707led |4kW, 0.9 lag S3 Solution: here S2= 12-jo·8 kVA S3= 4 +i 4. Sinto-g) = 4+jl.937 kA 0.9 here S4 5:2+jl·137 KVA 米 %3D 254 2152 +jl·137)x103 22-74- 104 now I Vo 100 296 hence Iz 22.74 +j104 A Similarly, si = 5- 2 sin Can-l(o-707)) = (1-;)kVA O.707 T,* = 251 (2-824 -i2-3234)XLO3 = - 28.234-j 28.284 A %3D 1 100 - 23.284+i 28. 284 A how Io = I, +I2= (22-74 +j lo 4)+(-23.284 -j 23-284 ) A - 5544 +j 132.23 =1 32:44 92-4° A %3D

Jun 11, 2022

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To I2 1.2kW 0-8KVA 100290° V 2KVA 0.707led |4kW, 0.9 lag S3 Solution: here S2= 12-jo·8 kVA S3= 4 +i 4. Sinto-g) = 4+jl.937 kA 0.9 here S4 5:2+jl·137 KVA 米 %3D 254 2152 +jl·137)x103 22-74- 104 now I Vo...

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