to achieve the lowest latency a message is split into 24 packets. every packet has 15 bytes of header. there are 11 hops between the source and the destination. Assume all devices are...

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to achieve the lowest latency a message is split into 24 packets. every packet has 15 bytes of header. there are 11 hops between the source and the destination. Assume all devices are store-and-forward and it takes 1 ns to transmit 1 byte of data. what is the size of the message?

Answered 116 days AfterJun 11, 2022

Answer To: to achieve the lowest latency a message is split into 24 packets. every packet has 15 bytes of...

Robert answered on Oct 06 2022

71 Votes

The message has a size of 165 bytes (15 bytes multiplied by 11 hops).
The message's latency is 165 bytes divided by 24 packets, or 6.875 ns.

The message's latency is 6.875 ns plus 1 ns (for the store-and-forward devices), for a total of 7.875 ns.

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to achieve the lowest latency a message is split into 24 packets. every packet has 15 bytes of header. there are 11 hops between the source and the destination. Assume all devices are...

Answer To: to achieve the lowest latency a message is split into 24 packets. every packet has 15 bytes of...

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