This gives us f (n+1) (c) I pla+)(t)(x – t)" dt (х — а)"+1. n +1 And the result follows. Problem 8.2.2. Prove Theorem 8.2.1 for the case where x

Extracted text: This gives us f (n+1) (c) I pla+)(t)(x – t)" dt (х — а)"+1. n +1 And the result follows. Problem 8.2.2. Prove Theorem 8.2.1 for the case where x < a.="" theorem="" 8.2.1.="" lagrange's="" form="" of="" the="" remainder="" suppose="" f="" is="" a="" function="" such="" that="" f(n+1)(t)="" is="" continuous="" on="" an="" interval="" containing="" a="" and="" x.="" then="" f(1)="" (a)="" f="" (n+1)="" (c)="" n="" f(x)="" –="" a)'="" (x="" –="" a)"+1="" -="" j!="" (n="" +="" 1)!="" where="" c="" is="" some="" number="" between="" a="" and="" x.="" in-context="" hint.="" note="" that="" i="" fla+1)="" (t)(x="" –="" t)"="" dt="(-1)"+1" f(a+)(t)(t="" –="" æ)"="" dt.="" f(n+1)="" (t)(t="" –="" x)"="" dt.="" t="a" t="x" use="" the="" same="" argument="" on="" this="" integral.="" it="" will="" work="" out="" in="" the="" end.="" really!="" you="" just="" need="" to="" keep="" track="" of="" all="" of="" the="">