Microsoft Word - ENSY_5000_2022_Fall_HW_08.docxENSY 5000 Fundamentals of Energy System Integration Homework Problem Set 8Submit your assignment as a pdf file to the Canvas for submission portal...

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Answered 3 days AfterNov 11, 2022

Answer To: Microsoft Word - ENSY_5000_2022_Fall_HW_08.docxENSY 5000 Fundamentals of Energy System Integration...

Dr Shweta answered on Nov 15 2022
60 Votes
Ans 1:
A) The exit temperature of air and heated water after passing through the recovery heat ex
changer is calculated as below:
Effectiveness ϵ = 80/100 = Th1-Th2/Th1-Tc1
As, Th1 = 753K
Tc1= 393 K
On putting values, we get,
Th2 = 465 K
Now Tc2 is calculated as
mhch (Th1-Th2) = mcCc (Tc1-Tc2) on putting the values of mh = 601.2 Kg/s, Ch = 2.5 kJ/ (kg K), mc=1257.74 Kg/s, Cc=4.18KJ/KgK
We get, Tc1 = 475 K
B) The entropy production rate in heat exchanger is calculated as:
δS = Q/T = 176.97 /288 = 0.61KW/K
C) Energy destruction rate in the heat exchanger
Edes = T0* δS
As T0 = 293 K
So, Edes = 180KW
(D) Find the entropy production rate of the air
δS = Q/T = 176.97 /82 = 2.16KW/K
(E) Energy destruction rate of the air
Edes = T0* δS
As T0 = 293 K
So, Edes = 633KW
(F) First law efficiency or Energy...
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