Theorem: "n and m are even numbers =nxm is an even number." Proof: Any even number a can be presented in the form a = 2k, where k is some integer number, therefore, let us write n and m in the form n...

provide solution/explanation

Extracted text: Theorem: "n and m are even numbers =nxm is an even number." Proof: Any even number a can be presented in the form a = 2k, where k is some integer number, therefore, let us write n and m in the form n = 2k1, m = 2k2, where k1, k2 are integers. The product is m x n = (2kj) × (2k2) = 2 × (2k,k2). Since k1, k2 are integer numbers, the twice the product of them will also be some integer number k3 = 2kkɔ. Thus, m x n = 2k3, where k3 is an integer, therefore the product of the integers n and m is even. The reasoning used here is O equivalence proof O backward reasoning O reductio ad absurdum. O forward reasoning