The vapour pressures of a compound can be given as: 2559.5 logp (mmHg) = 10.648– 1511 logp (mmHg) = 7.5396 – т alculate: a) the sublimation, melting and vaporisation enthalpies at the triple point“....

The vapour pressures of a compound can be given as:

Calculate: a) the sublimation, melting and vaporisation enthalpies at the triple point*.

b) p and T of the triple point.

* Beware we have decimal logarithms!

Extracted text: The vapour pressures of a compound can be given as: 2559.5 logp (mmHg) = 10.648– 1511 logp (mmHg) = 7.5396 – т alculate: a) the sublimation, melting and vaporisation enthalpies at the triple point“. b) p and T of the triple point. Beware we have decimal logarithms!