The topic is all about the Angular Motion of Particles. Please use pen and paper to solve and also use three decimal places. Please show the conversion solution. Thank you. Here are the formulas and...


The topic is all about theAngular Motion of Particles.Please use pen and paper to solve and also use three decimal places. Please show the conversion solution. Thank you.


Here are the formulas and discussion:



θ=θ_o+ω_o t+1/2 αt^2



ω=ω_0+αt



ω^2=ω_o^2+2α(θ-θ_o)


considering the tangential and normal components of the acceleration in a curvilinear motion of particles:



a_t=rα



a_n=rω^2=vω


The angular motion may be derived from the translational motion of particles by considering the given circle:



s=rθ


ds/dt=r dθ/dt           or
v=rω


dv/dt=r dω/dt           ora=rα



P.S. I provide also the answer but show me the complete solution on how to get that answer


Pulley B:<br>(RB),wB<br>40 × 12 = 20W B<br>WB = 24 rad/s «<br>(RB),CB<br>- 28 x 12 = 200B<br>aB = -16.8 rad/s?<br>a<br>Belt between B and C:<br>(RB);WB = 8(24) = 192 in./s<br>a'<br>(Rв); ав 3 8(-16.8) — — 134.4 in./s<br>%3D<br>Pulley C:<br>Rowc<br>192 = 24wC<br>wc = 8.0 rad/s<br>a'<br>Rcac<br>- 134.4 = 24ac<br>ac = -5.60 rad/s? 1<br>

Extracted text: Pulley B: (RB),wB 40 × 12 = 20W B WB = 24 rad/s « (RB),CB - 28 x 12 = 200B aB = -16.8 rad/s? a Belt between B and C: (RB);WB = 8(24) = 192 in./s a' (Rв); ав 3 8(-16.8) — — 134.4 in./s %3D Pulley C: Rowc 192 = 24wC wc = 8.0 rad/s a' Rcac - 134.4 = 24ac ac = -5.60 rad/s? 1
The velocity and acceleration of the belt running between the motor A and the pulley B are<br>v = 16

Extracted text: The velocity and acceleration of the belt running between the motor A and the pulley B are v = 16" and a = -9, respectively. Determine the angular velocities and angular accelerations of pulleys B and C. -100 250 A B V, a Dimensions in mm 00-

Jun 11, 2022
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