The simply supported beam AB as shown in Figure Q3(a) has a uniform load of intensity, w=15 kN/m acts throughout the entire length of the beam. The cross-section of the beam is shown in Figure Q3(b)....


The simply supported beam AB as shown in Figure Q3(a) has a uniform load of intensity,<br>w=15 kN/m acts throughout the entire length of the beam. The cross-section of the beam is<br>shown in Figure Q3(b). Given the second moment of area, INA = 36 x 106 mm“.<br>(a) Determine the shear stress at the top of the hole at section a-a.<br>(b) Determine the maximum shear stress at point M and N based on the maximum shear<br>force.<br>(c) Calculate the absolute maximum shear stress of the beam.<br>0.6 m<br>1.8 m<br>a.<br>w = 15 kN/m<br>В<br>Figure Q3 (a)<br>160<br>Ø30 hole<br>110<br>NA *<br>70<br>M<br>y = 80<br>40<br>N<br>100<br>All dimensions in mm<br>

Extracted text: The simply supported beam AB as shown in Figure Q3(a) has a uniform load of intensity, w=15 kN/m acts throughout the entire length of the beam. The cross-section of the beam is shown in Figure Q3(b). Given the second moment of area, INA = 36 x 106 mm“. (a) Determine the shear stress at the top of the hole at section a-a. (b) Determine the maximum shear stress at point M and N based on the maximum shear force. (c) Calculate the absolute maximum shear stress of the beam. 0.6 m 1.8 m a. w = 15 kN/m В Figure Q3 (a) 160 Ø30 hole 110 NA * 70 M y = 80 40 N 100 All dimensions in mm

Jun 10, 2022
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