The second multiple choice please, thank you. f(a) and b>a.B. The slope is negative because f(b) > f(a) and b a.Recall the Mean Value Theorem, which states the following. Suppose y = f(x) is...

The second multiple choice please, thank you.

Extracted text: Assume that fis differentiable on asxsb, afb, and that f(b) < f(a).="" show="" that="" f'="" is="" negative="" at="" some="" point="" between="" a="" and="" b.="" к)="" -="" (а)="" consider="" the="" line="" through="" the="" points="" (a.f(a))="" and="" (b.1(b))="" its="" slope="" is="" given="" by="" the="" formula="" m="-" choose="" the="" true="" b-a="" statement="" below.="" oa.="" the="" slope="" is="" positive="" because="" f(b)=""> f(a) and b>a. B. The slope is negative because f(b) > f(a) and ba. Recall the Mean Value Theorem, which states the following. Suppose y = f(x) is continuous on a closed interval (a,b] and differentiable on the interval's interior (a,b). Then there is at least one point c in (a,b) at which the slope of the tangent line at x= cis equal to the slope of the line through points (a,f(a) and (b.f(b). The two hypotheses of the Mean Value Theorem are (1) y =f(x) is continuous on a closed interval (a,b), and (2) y =f(x) is differentiable on the interval's interior (a,b). The given fact that fis differentiable on asxsbimplies which of the two hypotheses? Choose the correct answer below. A. (2) Ов. (1) Oc. (1) and (2)