The problem below should be in the form of a technical memo. Caicuiations should be attached (eg., a printout of an Excel spreadsheet or MATLAB solution. lateggpMINIIIMIMINEt Three design teams go to...

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The problem below should be in the form of a technical memo. Caicuiations should be attached (eg., a printout of an Excel spreadsheet or MATLAB solution. lateggpMINIIIMIMINEt
Three design teams go to Home Depot to buy supplies for assembling a water treatment system. The table below shows how many of each item they bought. Team
Tube of1Bracket Length of Total Amount caulk pipe Spent
A 2 4 6 $14.00 B 6 2 4 $11.00 C 4 6 3 2 $11.00
How much did each item cost?
Use MATLAB or Excel to complete the problem. Show all work including code when submitting.



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Three design go teams to Home Depot to buy sirpplies for assembling a water treatment system. The table below shows how many of each item they bought. Length of TotalAmount Bracket pipe Spent 6i Sr+.oo Ai How much did each item cost? Use MATLAB or Excel to complete the problem. Show all work including code when submitting.






Three design teams go to Home Depot to buy sirpplies for assembling a water treatment system. The table below shows how many of each item they bought. Bracket How much did each item cost? Use MATLAB or Excel to complete the problem. Show all work including code when submitting. Length of pipe TotalAmount Spent 6i Ai Sr+.oo
Answered Same DayDec 20, 2021

Answer To: The problem below should be in the form of a technical memo. Caicuiations should be attached (eg., a...

David answered on Dec 20 2021
126 Votes
The cost of Tube of caulk is $0.5, cost of Bracket is $1 and cost of Length of pipe = $1.5
The MAT
LAB Codes along with the outputs is given below:
>> syms x y z positive
>> F1 = 2*x + 4*y + 6*z - 14
F1 =
2*x + 4*y + 6*z - 14
>> F2 = 6*x + 2*y + 4*z - 11
F2 =
6*x + 2*y + 4*z - 11
>> F3 = 4*x + 6*y + 2*z - 11
F3 =
4*x + 6*y + 2*z - 11
>> S = solve ( F1, F2, F3, x, y, z)
S =
x: [1x1 sym]
y: [1x1 sym]
z: [1x1 sym]
>> S.x
ans =
1/2
>> S.y
ans =
1
>> S.z
ans =
3/2
>> double(S.x)
ans =
0.5000
>>...
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