The periodogram IN (f ) evaluated at Fourier frequencies f = k/N is unaffected by whether or not the data are centered by the mean. Demonstrate this (mathematically) by showing that
a∗ j = N−1 t=0 (yt − ¯y) exp −2πijt N "
is the same as
aj = N−1 t=0 yt exp −2πijt N "
for all j = 0.
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