The performance of students at a local community was recorded and categorized based on student’s faculty. The gathered data was then analyzed by a statistician and the results obtained using MINITAB...

The performance of students at a local community was recorded and categorized based on student’s faculty. The gathered data was then analyzed by a statistician and the results obtained using MINITAB are shown below:

Expected counts are printed below observed counts.

Chi - sq = 0.858 + 0.020 + *** +

                 1.042     0.000 + 0.350 +

                 0.030 + 0.104 + 0.023 = 2.600

i. What is the degree of freedom for this test?
ii. Estimate the p-value for this test.
iii. State the conclusion for the test. Give a reason for your answer.