The null and alternate hypotheses are: H 0 : μ d ≤ 0 H 1 : μ d > 0 The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample...

The null and alternate hypotheses are:

H
₀ :μ_d
 ≤ 0

H
₁ :μ_d
 > 0

The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month.

At the 0.100 significance level, can we conclude there are more defects produced on the day shift?Hint:For the calculations, assume the day shift as the first sample.

1. 
   

   State the decision rule.(Round your answer to 2 decimal places.)
   

   
   

1. 
   

   Compute the value of the test statistic.(Round your answer to 3 decimal places.)
   

   
   

1. 
   

   What is thep-value?

   
   

multiple choice 1

• 
  
  
  

  Between 0.025 and 0.05

  
  
  
  


• 
  
  
  

  Between 0.001 and 0.005

  
  
  
  


• 
  
  
  

  Between 0.005 and 0.01

  
  
  
  

1. 
   

   What is your decision regardingH
   ₀?

   
   

multiple choice 2

• 
  
  
  

  RejectH
  ₀
  

  
  
  
  


• 
  
  
  

  Do not rejectH
  ₀