The null and alternate hypotheses are: H 0 :μd ≤ 0 H 1 :μd > 0The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month. Day 1 2 3 4 Day shift 10 11 14 18 Afternoon shift 9 10 13 18 At the 0.010 significance level, can we conclude there are more defects produced on the day shift?Hint:For the calculations, assume the day shift as the first sample.a. State the decision rule.b. Compute the value of the test statistic.c. What is thep-value?d. What is your decision regardingH 0?

The null and alternate hypotheses are: H 0 : μ d ≤ 0 H 1 : μ d > 0 The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample...

The null and alternate hypotheses are:

H
₀ :μ_d
≤ 0

H
₁ :μ_d
> 0

The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month.

	Day
	1	2	3	4
Day shift	10	11	14	18
Afternoon shift	9	10	13	18

At the 0.010 significance level, can we conclude there are more defects produced on the day shift?Hint:For the calculations, assume the day shift as the first sample.

a. State the decision rule.

b. Compute the value of the test statistic.

c. What is thep-value?

d. What is your decision regardingH
₀?

Jun 09, 2022

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The null and alternate hypotheses are: H 0 : μ d ≤ 0 H 1 : μ d > 0 The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample...

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