Answer To: The instructions for each problem set are provided on the web via the problem set link that is...
Himanshu answered on Feb 04 2021
Research Problem #5:
Research Method 10RM – Chi Square
Part 1 Relationship between Variables
Df is 1
Pearson Chi Square is 41.41.
5,782.2 males and 6163.9 females and 8804.4 that have not consumed smoked cigarettes and 3087.7 who have.
p=0.00 after the value of Chi Square.
Criteria for dismissing the null hypothesis: if the significance of value is less than.05, as <0.005 is less than.05, we dismiss the null hypothesis.
Expected values
Expected frequencies = (row marginal *column marginal)/ (total number of cases)
(8,804.4 * 5,728.2)/ (11,892.1) = 4,240.9
Males who will not smoke cigarettes will be 4,240.9.
Expected frequencies = (row marginal *column marginal)/ (total number of cases)
(8,804.4 * 6,163.9)/ (11,892.1) = 4,563.4
Females who will not smoke cigarettes will be 4,563.4.
Expected frequencies = (row marginal *column marginal)/ (total number of cases)
(3,087.7 * 5,728.2)/ (11,892.1) = 1,487.2
Males who will smoke cigarettes will be 1,487.2.
Expected frequencies = (row marginal *column marginal)/ (total number of cases)
(3,087.7 * 6,163.9)/ (11,892.1) = 1,600.4
Females who will smoke cigarettes will be 1,600.4.
Pearson Chi Square is 3.28.
degrees of freedom (df) is 1.
5,639.3 males and 6081.4 females and 6,475.6 that have not ever used marijuana or hashish and 5,245.1 who have.
Criteria for dismissing the null hypothesis, if the significance of value is less than.05 as <0.07 is greater than 0.05, we cannot deny the null hypothesis. Accepting the null hypothesis would mean that you have demonstrated that there is no...