The following table shows the acetone mols adsorbed on active carbon per gr of carbon, at a function of the concentrations, at 18 ºC. a) Which is the most adequate isotherm: Langmuir, Temkin or...

The following table shows the acetone mols adsorbed on active carbon per gr of carbon, at a function of the concentrations, at 18 ºC.
a) Which is the most adequate isotherm: Langmuir, Temkin or Freundlich? Justify
b) Calculate the magnitudes relevant for the chosen isotherm.
Since the adsorption is given in a liquid solution, c and s are, respectively, equivalent to pressure (p) and adsorbed volume (v).

Results: a) Freundlich isotherm is the most adequate: log s = -0.8751 + 0.5459 log c, R = 0.99978. (Langmuir R = 0.983; Temkin: R = 0.9745).

b) k = 0.139 mmol Acet./g C and a = 0.5459.

Extracted text: a function of the concentrations, at 18 °C. c ( mmol/cm³) 84 165 390 800 s (mmol acet./g C) 1.50 2.15 3.50 5.10 a) Which is the most adequate isotherm: Langmuir, Temkin or Freundlich? Justify b) Calculate the magnitudes relevant for the chosen isotherm. Since the adsorption is given in a liquid solution, c and s are, respectively, equivalent to pressure (p) and adsorbed volume (v). Results: a) Freundlich isotherm is the most adequate: log s = -0.8751 + 0.5459 log c, R = 0.99978. (Langmuir R = 0.983; Temkin: R = 0.9745). b) k = 0.139 mmol Acet./g C and a = 0.5459.