The following parallel arrays store intormation about 1000 apartments in Jordan. Live Sessions Time Running: Hide Attempt due: Feb 3 at 12:15pm • string city[1000]; // store the cities where these...

Using C++ language
The following parallel arrays store intormation about 1000 apartments in Jordan.<br>Live Sessions<br>Time Running: Hide<br>Attempt due: Feb 3 at 12:15pm<br>• string city[1000]; // store the cities where these apartments are located<br>• int bedRooms[1000]; // store the number of bedrooms in each apartment<br>• int price[1000]; // store the price of each apartment<br>55 Minutes, 2 Seconds<br>Which of the following code segments calculate the average price of all apartments<br>which have three or more bedrooms and not located in Irbid. The result stored in the<br>variable =3 && city[i] == "Irbid") X++; x /-1000; int x-0; for (int i-0;i<1000;i++) {="" if(bedrooms="" [i]="">=3 && city[i] !- "Irbid") x += price[i]; x /-1000; O All the answers are correct int x-e; for (int i-0;i<1000;i++) {="" if(bedrooms="" [i]="">-3 && city[i] -- "Irbid") X++; int x-0; for(int i-0;i<1000;i++) {="" if(bedrooms="" [1]="">=3 && city[i) =- "Irbid") x +- price[i]; x /-1000 "/>
Extracted text: The following parallel arrays store intormation about 1000 apartments in Jordan. Live Sessions Time Running: Hide Attempt due: Feb 3 at 12:15pm • string city[1000]; // store the cities where these apartments are located • int bedRooms[1000]; // store the number of bedrooms in each apartment • int price[1000]; // store the price of each apartment 55 Minutes, 2 Seconds Which of the following code segments calculate the average price of all apartments which have three or more bedrooms and not located in Irbid. The result stored in the variable "x". int x-0; for(int i-0;i<1000;i++) {="" if(bedrooms="" [i]="">=3 && city[i] == "Irbid") X++; x /-1000; int x-0; for (int i-0;i<1000;i++) {="" if(bedrooms="" [i]="">=3 && city[i] !- "Irbid") x += price[i]; x /-1000; O All the answers are correct int x-e; for (int i-0;i<1000;i++) {="" if(bedrooms="" [i]="">-3 && city[i] -- "Irbid") X++; int x-0; for(int i-0;i<1000;i++) {="" if(bedrooms="" [1]="">=3 && city[i) =- "Irbid") x +- price[i]; x /-1000

Jun 08, 2022
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