The following MINITAB output presents the results of a hypothesis test for a population mean u. One-Sample Z: X Test of mu = 45 vs > 45 The assumed standard deviation = 5.0921 Variable N Mean StDev SE...

The following MINITAB output presents the results of a hypothesis test for a population<br>mean u.<br>One-Sample Z: X<br>Test of mu = 45 vs > 45<br>The assumed standard deviation = 5.0921<br>Variable N Mean StDev<br>SE<br>95% Lower z P<br>Mean<br>Bound<br>х<br>12246.2598 5.0921 0.4610<br>45.50152.730.003<br>Is this a one-tailed or two-tailed test?<br>a.<br>b.<br>What is the null hypothesis?<br>C.<br>What is the P-value?<br>d.<br>Use the output and an appropriate table to compute the P-value for the test of Họ: µ S<br>46 vs. H1: µ > 46.<br>Use the output and an appropriate table to compute a 98% confidence interval for u.<br>e.<br>

Extracted text: The following MINITAB output presents the results of a hypothesis test for a population mean u. One-Sample Z: X Test of mu = 45 vs > 45 The assumed standard deviation = 5.0921 Variable N Mean StDev SE 95% Lower z P Mean Bound х 12246.2598 5.0921 0.4610 45.50152.730.003 Is this a one-tailed or two-tailed test? a. b. What is the null hypothesis? C. What is the P-value? d. Use the output and an appropriate table to compute the P-value for the test of Họ: µ S 46 vs. H1: µ > 46. Use the output and an appropriate table to compute a 98% confidence interval for u. e.

Jun 10, 2022

SOLUTION.PDF

The following MINITAB output presents the results of a hypothesis test for a population mean u. One-Sample Z: X Test of mu = 45 vs > 45 The assumed standard deviation = 5.0921 Variable N Mean StDev SE...

Get Answer To This Question

Related Questions & Answers

Submit New Assignment