The following data are from a completely randomized design. Treatment Treatment Treatment A B 32 44 33 30 43 36 30 44 35 26 46 36 32 48 40 Sample mean 30 45 36 Sample variance 6.00 4.00 6.50 a. At the...

Please assist in this multiple comparison problem.

Extracted text: The following data are from a completely randomized design. Treatment Treatment Treatment A B 32 44 33 30 43 36 30 44 35 26 46 36 32 48 40 Sample mean 30 45 36 Sample variance 6.00 4.00 6.50 a. At the a = 0.05 level of significance, can we reject the null hypothesis that the means of the three treatments are equal? Compute the values below (to 1 decimal, if necessary). Sum of Squares, Treatment Sum of Squares, Error Mean Squares, Treatment Mean Squares, Error Calculate the value of the test statistic (to 2 decimals). The p-value is between 0.01 and 0.025 What is your conclusion? Conclude that not all treatment means are equal v b. Calculate the value of Fisher's LSD (to 2 decimals).


Extracted text: Use Fisher's LSD procedure to test whether there is a significant difference between the means for treatments A and B, treatments A and C, and treatments B and C. Use a = 0.05. Difference Absolute Value Conclusion TA - TB Significant difference TA - TC Significant difference Significant difference c. Use Fisher's LSD procedure to develop a 95% confidence interval estimate of the difference between the means of treatments A and B (to 2 decimals). Enter negative values as negative numbers.