The following data are from a completely randomized design. Treatment Treatment Treatment A B C 32 46 35 30 45 38 30 46 37 26 48 38 32 50 42 Sample mean 30 47 38 Sample variance 6.00 4.00 6.50 a. At...

the answer for part b was given to me by a tutor 3.79 and the system shows that is incorrect, please help where the red x is.

Extracted text: The following data are from a completely randomized design. Treatment Treatment Treatment A B C 32 46 35 30 45 38 30 46 37 26 48 38 32 50 42 Sample mean 30 47 38 Sample variance 6.00 4.00 6.50 a. At the a = 0.05 level of significance, can we reject the null hypothesis that the means of the three treatments are equal? Compute the values below (to 1 decimal, if necessary). Sum of Squares, Treatment 723.3 Sum of Squares, Error 66 Mean Squares, Treatment 361.7 Mean Squares, Error 5.5 Calculate the value of the test statistic (to 2 decimals). 65.76 The p-value is less than 0.01 What is your conclusion? Conclude that not all treatment means are equal b. Calculate the value of Fisher's LSD (to 2 decimals). 3.79)3 Use Fisher's LSD procedure to test whether there is a significant difference between the means for treatments A and B, treatments A and C, and treatments B and C. Use a = 0.05.