The first reaction in Glycolysis is the phosphorylation of Glucose: Pi + Glucose - Glucose 6-Phosphate + water This is a thermodynamically unfavorable process with a AG,' = +13.8 kJ/mol. In a liver...

Extracted text: The first reaction in Glycolysis is the phosphorylation of Glucose: Pi + Glucose - Glucose 6-Phosphate + water This is a thermodynamically unfavorable process with a AG,' = +13.8 kJ/mol. In a liver cell at 37°c the concentrations of both phosphate and glucose are normally maintained at about 0.005 M each. What would be the equilibrium concentration of Glucose 6-Phosphate according to the above data? Note: In the biochemical standard state [H2O] = 1.0 Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a 0.00000012 0.0000025 0.00000025 0.00474 e 0.005 1.0 0.1 h 0.25 i 2.4