The first approximation(p;) of the root of the equation f(x) = x- cos(x)=0 by Newton Raphson method with po=0.5 is None of these 0.63468 1.28475 0.64368 1.24875 Click Save and Submit to save and...

The first approximation(p;) of the root of the equation f(x) = x- cos(x)=0<br>by Newton Raphson method with po=0.5 is<br>None of these<br>0.63468<br>1.28475<br>0.64368<br>1.24875<br>Click Save and Submit to save and submit. Click Save All Answers to save all answers.<br>Save All Ans<br>

Extracted text: The first approximation(p;) of the root of the equation f(x) = x- cos(x)=0 by Newton Raphson method with po=0.5 is None of these 0.63468 1.28475 0.64368 1.24875 Click Save and Submit to save and submit. Click Save All Answers to save all answers. Save All Ans

Jun 05, 2022

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The first approximation(p;) of the root of the equation f(x) = x- cos(x)=0 by Newton Raphson method with po=0.5 is None of these 0.63468 1.28475 0.64368 1.24875 Click Save and Submit to save and...

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