| The electrical network shown can be viewed as con- sisting of three loops. Applying Kirchoff's law (Evoltage drops = Evoltage sources) to each loop yields the following equations for the loop cur-...


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| The electrical network shown can be viewed as con-<br>sisting of three loops. Applying Kirchoff's law<br>(Evoltage drops = Evoltage sources)<br>to each loop yields the following equations for the loop cur-<br>rents i1, i2, iz:<br>20 Ω<br>5Ω<br>mn-220 V<br>ww<br>i,<br>iz<br>-OV<br>www<br>102<br>5i1 + 15(i1 – i3)<br>= 220 V<br>R(i2 – i3) + 5i2 + 10i2<br>= 0<br>20i3 + R(i3 – i2) + 15(i3 – i1)<br>= 0<br>%3D<br>Compute the three loop currents in terms of R.<br>152<br>wwww<br>www<br>

Extracted text: | The electrical network shown can be viewed as con- sisting of three loops. Applying Kirchoff's law (Evoltage drops = Evoltage sources) to each loop yields the following equations for the loop cur- rents i1, i2, iz: 20 Ω 5Ω mn-220 V ww i, iz -OV www 102 5i1 + 15(i1 – i3) = 220 V R(i2 – i3) + 5i2 + 10i2 = 0 20i3 + R(i3 – i2) + 15(i3 – i1) = 0 %3D Compute the three loop currents in terms of R. 152 wwww www

Jun 11, 2022
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