The efficiency for a steel specimen immersed in a phosphating tank is the weight of the phosphate coating divided by the metal lass (bath in mg/ft). An article gave tha accompanying data on tank...

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Extracted text: The efficiency for a steel specimen immersed in a phosphating tank is the weight of the phosphate coating divided by the metal lass (bath in mg/ft). An article gave tha accompanying data on tank temparature (x) and efficiency ratio (y). Temp. 173 175 176 177 177 178 179 180 Ratio 1.27 1.34 1.01 1.05 1.no 0.08 0.86 1.70 Temp. 194 184 183 183 183 183 193 185 Ratio 1.65 2.15 2.13 0.94 1.41 1.51 1.50 1.00 Temp. 187 185 185 185 187 188 189 191 Ratio 1.83 2.00 1.57 2.62 2.70 3.02 1.03 3.00 A USE SALT (a) Dotermine the oquation of the astimated regression lina. (Round all numerical values to four decimal places.) y - -16.576 + 0.1000x (b) Calculate a point estimate for true average efficiency ratio when tank termperature is 185. (Round your answer to four decimal places.) 1.924 (c) Calculate the values of the residuals fronm the least squares line for the four observations for which temperature is 185. (Round your answers to two decimal places.) (185, 1.00) -0.92 (185, 1.83) -0.09 x Your answer cannot be understood or graded. More Information (185, 2.00) 0.08 (185, 2.70) 0.00 (d) What proportion of the observed variation in efficiency ratio can be attributed to the simple linear regression relationship between the two variables? (Round your answer to three decimal places.)