The dissociation of 0.15 M phosphoric acid is given by:
H3PO4(aq) + H2O(l) ⇄ H2PO4^-(aq) + H3O^+(aq)
Ka = 7.1 x 10-3 (at 25°C)
H2PO4^-(aq) + H2O(l) ⇄ HPO4^2-(aq) + H3O^+(aq)
Ka = 6.3 x 10-8 (at 25°C)
HPO4^2-(aq) + H2O(l) ⇄ PO4^3-(aq) + H3O^+(aq)
Ka = 4.5 x 10^-13
B. Applying the systematic method in solving acid-base equilibria problems, calculate the pH of the following
d. 0.050 M Na3PO4
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