The claim is that smokers have a mean cotinine level greater than the level of 2.84 ng / mL found for nonsmokers. (Cotinine is used as a biomarker for exposure to nicotine.) The sample size is n= 738...


The claim is that smokers have a mean cotinine level greater than the level of 2.84 ng / mL found for nonsmokers. (Cotinine is used as a biomarker for exposure<br>to nicotine.) The sample size is n= 738 and the test statistic is t= 54.846. Use technology to find the P-value. Based on the result, what is the final conclusion?<br>Use a significance level of 0.10.<br>State the null and alternative hypotheses.<br>Ho H<br>H:H<br>(Type integers or decimals. Do not round.)<br>The test statistic is.<br>(Round to two decimal places as needed.)<br>The P-value is<br>(Round to three decimal places as needed.)<br>V the claim that smokers have a mean cotinine level<br>V sufficient evidence at a significance level of 0.10 to<br>Based on the P-value, there<br>greater than the level of 2.84 ng / mL found for nonsmokers.<br>

Extracted text: The claim is that smokers have a mean cotinine level greater than the level of 2.84 ng / mL found for nonsmokers. (Cotinine is used as a biomarker for exposure to nicotine.) The sample size is n= 738 and the test statistic is t= 54.846. Use technology to find the P-value. Based on the result, what is the final conclusion? Use a significance level of 0.10. State the null and alternative hypotheses. Ho H H:H (Type integers or decimals. Do not round.) The test statistic is. (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) V the claim that smokers have a mean cotinine level V sufficient evidence at a significance level of 0.10 to Based on the P-value, there greater than the level of 2.84 ng / mL found for nonsmokers.

Jun 03, 2022
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